Gujarati
Hindi
4-1.Newton's Laws of Motion
medium

A boy is hanging from branch of a tree as shown. Angle between his arm, for tension to be maximum in arms must be ............ $^o$

A

$60$

B

$74$

C

$90$

D

$120$

Solution

$2 \mathrm{T} \cos \frac{\theta}{2}=\mathrm{Mg}$ for equillibrium

$\mathrm{T}=\frac{\mathrm{Mg}}{2 \cos \frac{\theta}{2}}$

for $T$ to be maximum cos $\frac{\theta}{2}$ must be minimum so

$\frac{\theta}{2}$ must be maximum

Standard 11
Physics

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