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4-1.Newton's Laws of Motion
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A boy is hanging from branch of a tree as shown. Angle between his arm, for tension to be maximum in arms must be ............ $^o$

A
$60$
B
$74$
C
$90$
D
$120$
Solution
$2 \mathrm{T} \cos \frac{\theta}{2}=\mathrm{Mg}$ for equillibrium
$\mathrm{T}=\frac{\mathrm{Mg}}{2 \cos \frac{\theta}{2}}$
for $T$ to be maximum cos $\frac{\theta}{2}$ must be minimum so
$\frac{\theta}{2}$ must be maximum
Standard 11
Physics
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